x=(4x^2-4x+8)+(x^2+2x+7)

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Solution for x=(4x^2-4x+8)+(x^2+2x+7) equation: 



x=(4x^2-4x+8)+(x^2+2x+7)

We move all terms to the left:

x-((4x^2-4x+8)+(x^2+2x+7))=0



We calculate terms in parentheses: -((4x^2-4x+8)+(x^2+2x+7)), so:

(4x^2-4x+8)+(x^2+2x+7)

We get rid of parentheses

4x^2+x^2-4x+2x+8+7

We add all the numbers together, and all the variables

5x^2-2x+15

Back to the equation:

-(5x^2-2x+15)



We get rid of parentheses

-5x^2+x+2x-15=0

We add all the numbers together, and all the variables

-5x^2+3x-15=0

a = -5; b = 3; c = -15;
Δ = b2-4ac
Δ = 32-4·(-5)·(-15)
Δ = -291
Delta is less than zero, so there is no solution for the equation

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